-12x^2-60x-48=0

Solution for -12x^2-60x-48=0 equation:

-12x^2-60x-48=0

a = -12; b = -60; c = -48;
Δ = b2-4ac
Δ = -602-4·(-12)·(-48)
Δ = 1296
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{1296}=36$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-60)-36}{2*-12}=\frac{24}{-24}
=-1
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-60)+36}{2*-12}=\frac{96}{-24}
=-4
$